If I remember correctly, one of the areas they will be bulk sampling is the area where they intersected 2393 g/t Au over 10.7m.

Now for some math fun. Assume those grades are consistent over a 1m x 1m square** and for the full 10.7m depth.

10.7 cubic meters x 2.54 tonnes / cubic meter = 27.2 tonnes

27.2 tonnes x 2393 g/t = 65,090 grams of gold = 2093 troy ounces of gold

2093 troy ounces of gold x $1658 / oz = $3.5 million

So with these assumptions, 10.7 cubic meters of rock could contain $3.5M in gold. Of course these numbers are astronomically high and they won't be taken seriously until the bulk sample validates the data.

**I've got no idea if this is a valid assumption, but previous high grade intersepts are typically 0.5m - 1m in length