These calculations are not totally accurate, but close enough for me to demonstrate something. Anybody can add or take away from them, and thoughts are welcome.

1) we know that in 2008 that there was 4000t of bulk sample removed from the property. It had an average grade of over an ounce per ton but I will use 30 g/t in my calcs.

2) if we were to stretch that tonnage out by saying 1 g/t, we would multiply 4000t by 30 to get 120000t at 1g/t.

3)if we take this a step further and see how many meters cube that would be, we get 48m cubed.

4) I had known exactly how far the veins in the Zona Canchete, C-1,C-2,C-3,C-4, were apart, (but forget, and for the sake of this, i am not going back through releases to find the exact distances.) I beleive that the 4 gold bearing veins all lie within 120ms, or 30m apart. These veins have grades as high as 5 plus ounces of gold in some of them, if not all.

5) So, you should be able to see how easy it is of having an average of 1g/t in this area, because my math shows that 1 g/t would be 48 m cubed, and our veins are only 30 m apart. This allows for overlapping of high grades AND most importantly its giving that 30m between veins a GRADE OF 0!

6) SO, SHOULDN,T IT BE VERY EASY TO BELEIVE THAT WE COULD AVERAGE 1G/T GOLD OVER THE ENTIRE PROPERTY. And, if we did average 1g/t over the entire property to a depth of 100m, I beleive that still gives you close to a million ounces. And to be conservative, say it gives us 50 million ounces. So, really, we dont need whats below 100m to justify a stock price of $70.

COMMENTS PLEASE!