For the newer members, towards the end of Feb. there was a lot of interesting posts regarding the volume of the ovoid beneath Zona Central and partly Zona Canchete. Since then we have learned that the larger pink colour had been faded so there would be less confusion. In addition interpretation of the chargeability numbers of the anomaly are high for both the red and the pink coloured parts of the structure.

To review, the formula for an ovoid is 4/3 pi x n "n" is the radius of the length, width and height, or ½ of 1800, 1700 and 1300

Pi x n (497 million) is 1562.7m x 4/3 is 2083 m cu meters. Multiply x 2.5 to give 5307 m t Multiply by .68 scaling factor to get rid of “non ore” rock = 3540 million tonness of ore. Divide by 31 to arrive @ 114 million tons of gold for the anamoly

I unpacked my silly putty and made another model of the ovoid. Because there are only plan and elevation pictures available, without multiple cross sectional views it is not possible to build a scale model accurately. However, the second model was slightly different from the first, but when it was dismantled and rolled into a 2” cylinder, the height was the same as the first, viz. 3.5” However the initial calculation was not correct because of the error in the scaling factor etc. Herewith are the new calculations for the two cylinders, the pink ovoidand the inner red portion of the ovoid. My scale is 866 meters equal 1”

My numbers are much higher than the calculations that were posted at the end of February for an ovoid. The confines of only two dimensions did not lead to much of an ovoid. At both the north and south ends I could visualize an ovoid similar to the first survey when the beginning of the ovoid was discovered. However, as one progressed, the walls had to be much steeper to reach the confines of the midpoint of the cardboard longitudinal template I was using. The finished shape was bowl-like, but a bowl with very steep sides, closer to a rectangle rather than an ellipsoid if you ignored the thinner ends. With only the single cross section (see Hog’s library photo Phase1 3D Image of Ovoid, & primed picture showing the cross section location -http://primed24.files.wordpress.com/2011/03/the-big-picture2.jpg), it wasn’t logical to continue this oval shape and still meet the rigidity of the two dimensions I had to work with. The greatest error is in the model being too fat, rather than errors of rolling the putty into a cylinder and calculating the volume of a cylinder. There is some error there, but small. I tried two 1” columns but they had rounded edges. If I had a lab type of graduated cylinder you could displace the water and get an accurate reading, but as I said, the greatest error is in the model itself. Management said the anomaly was bowl shaped. My anomaly had steep sides and the formula for an ellipsoid (without calculus taking slices) is an ellipsoid and this is the (first above) formula you have to use. My Devil's Advocate findings are based on the volume model and the error is probably much too large, but time will tell.

Volume of a cylinder is r2 x pi x height. Diameter is 2” Pink cylinder is 3.5” high; red (inner) part of the anomaly diameter is 2” and the height is 1 7/8”

1. For the whole (pink) portion is 866x866=749956 x22/7 =2.3 million x height of 3.5” (3031m) = 7138 million cu meters of conducting rock

2. .For the red inner “(higher grade”) calculations: 2.3 million x 1624 =2355 m3 of rock,

3. Subtract 2355 from the gross 7138= 4783 million meters of net pink conductive rock. (outside of the red). Multiply x 2.5 for tonnage = 11957 m. t. x scaling factor of 0.68 =8130 million tonnes of ore. @ i gm/t divide by 31 gives 262 million ounces of gold.

4. For the red portion, 2355 x 2.5 = 5887 x 0.68 = 4003 m.t. Divide by 31 = 129 million ounces

5. Total ounces then is 262+129 = 391 m ounces

The Red is likely to be very high grade,and the pink not as far behind as I originally surmised, (since they later said the colour was muted for clarity) The fact that the total ounces in my model calculations is 3+ times higher is not that important because the grades that the drills turn up will tell the story. For example, with 114 m tonnes, cores grading 24 oz. per ton would give 2736 m. ounces. Whereas a 391 size, cores of 2 oz x returns 782 million ounces.

The conclusion is if you look at the pictures and see the tiny depths of the shafts in relation to the anomaly, without any figures at all, one must be impressed that that is one huge anomaly!