Thought that this calculation might be very interesting.
Lets look at BB1. From microprobe analyses of the chromite we know that it contains 35.5% Cr (51.9% Cr2O3)with a Cr:Fe ratio of 1.72. Hence, it contains 20.6% Fe. Combined Cr+Fe=56.1%. One drill core intersection assay gave 39.1% Cr2O3==>75 wt% chromite.
Therefore, 1 tonne chrome ore contains 0.75 x 2204=1653 lb chromite
56.1% Cr+Fe per lb chromite=927 lb Cr+Fe (i.e. ferrochrome)
Price of ferrochrome approx $1/lb
Therefore, value of 1 tonne chrome ore from BB1=$927
Lets look at a Ni ore
Price of Ni approx $10,000/tonne==>$4.50/lb
For an equivalent value/tonne, 1 tonne Ni ore would have to contain $972/$4.50=206 lb Ni==>9.3% Ni equivalent
Please check my calculations someone.
Thanks
geoprof