In the last interview a figure of 20% copper was mentioned. Is that correct?
Does that mean that if 100 lbs of rock is extracted that 20lbs of copper
would be required to be found to warrant further drilling?

MaybeSoon, Thank you for that ? I have been contemplating the "20%" meaning also.


Consider IF: Rock weighs around 20 lbs. per cu. ft.
9 cu. ft. per cu. yd. = 180 lbs. per cu. yd. of rock
20% copper yields 36 lbs per cu. yd.


A hole 100 yds. square and 50 yds. deep yields 18 million lbs of copper.
$2.34 per lbs. = $42 million - Minus digging and smelting expenses of course.
for a shallow hole twice the size of a football field?


This is ludicrous.

Nevada Copper Intersects 105 Feet of 2.55% Copper in the East Deposit

http://www.marketwired.com/press-release/-2069630.htm

NC15U-02 encountered several zones of high grade mineralization,
the largest intersecting 26.4 meters (86.6 feet @ 2.79% Cu) 24.8 meters true thickness.

NC15U-03 intersected several higher grade zones within a large zone of mineralization,
the larger zone intersected 120.1 meters (394.0 feet @ 1.21% Cu) true thickness.

NC15U-06 intersected a very broad zone of mineralization intersecting 176.8 meters
(580.0 feet @ 1.01% Cu) 166.1 meters true thickness that extended beyond the
existing designed stopes.

Sorry Nevada Copper, why bother. 2.79% Cu. indeed!!