HIGH-GRADE NI-CU-PT-PD-ZN-CR-AU-V-TI DISCOVERIES IN THE "RING OF FIRE"

NI 43-101 Update (September 2012): 11.1 Mt @ 1.68% Ni, 0.87% Cu, 0.89 gpt Pt and 3.09 gpt Pd and 0.18 gpt Au (Proven & Probable Reserves) / 8.9 Mt @ 1.10% Ni, 1.14% Cu, 1.16 gpt Pt and 3.49 gpt Pd and 0.30 gpt Au (Inferred Resource)

Free
Message: If in fact 50% of Windfall is sold

NowWhat, I concur. I was not the one who suggested that 40-50% of Windfall had or will be sold for $100MM. I was simply carrying forward the thought process. Hopefully everyone reading the posts can formulate their own conclusions based on the information/speculation provided.

As some have mentioned that they believe this to be a possibility, I am attempting to establish what the Windfall property would be worth (without having a formal 43-101 in hand).

In order for a third party to belly up and pay $100MM, how much much gold reserves must be "deemed" to be present? Let's use your example of Goldcorp purchasing Golden Eagle for $62 per ounce in-situ. If we use the 3 year trailing average price for gold - $650.00, Goldcorp paid 9.5% in-situ.

With the above in mind, how much gold would have to be present for a third party to pay $100MM for 50%?

$200MM/.095 = $2.105Bn

$2.105Bn/$650 = 3.2 million ounces

So, for anyone subscribing to the theory that half of Windfall has been sold for $100MM, this shows a rough, down & dirty calculation.

------------------------------------...

Now, for a little bit of fun. How many cubic metres of ore at 52 ounces per tonne is required to contain 3.2 million ounces?

3.2MM / 52 = 61,538 tonnes

61,538 / 2.5 specific gravity = 24,615 cubic metres

roughly 29 x 29 x 29 metres.

Cheers,



Milsy1

Share
New Message
Please login to post a reply