By george, I think I've got it. (please correct me if I'm mistaken)

The composition of the chromite grains themselves are critical in determining how much chromite by weight is contained within each tonne of rock. As per the May 27/08 N/R:

Wavelength dispersive electron microprobe analysis of 90 individual chromite grains in samples from holes NOT-08-1G3 (134 m) and NOT-08-1G20 (247 m) show that the compositions of the chromite grains show little variability around an average value of 51.9 weight percent Cr2O3. (Is it correct to assume that this composition is not necessarily representative of the entire deposit? I suspect that it is not but it is the only factual information that we have to work with at this time).

So, knowing our 51.9 weight percentage Cr2O3, we can use this in conjunction with our assays received to date to determine the amount of chromite ore in each tonne of rock.

NOT-08-1G17 assayed 39.1% Cr2O3

Therefore 39.1/51.9 = 75.3 Wt

75.3% X 2204 lbs/tonne = 1659.6 lbs chromite ore/tonne

NOT-08-1G25 assayed 24.9% Cr2O3

Therefore 24.9/51.9 = 48.0 Wt

48.0% X 2204 lbs/tonne = 1057.9 lbs chromite ore/tonne

etc.

I much as I think I get it, again, please correct me if I am mistken.

Cheers,

Milsy1